Recursion algorithms can be analysed by 3 methods : Substitution method,recursion tree method and master method.
1)Show that the solution of T(n)=T(n/2) + 1 is O(lg n).
2)Show that the solution to T(n)=2*T((n/2)+17) is O(n*(lg n)).
3)Solve the recurrence T(n)=2*T(sqrt(n)) + 1.
4)Use a recursion tree to determine a good asymptotic upper bound on the recurrence T(n)=3*T(n/2) + n.
5)Use a recursion tree to give an asymptotically tight solution to the recurrence T(n)=T(n-a) + T(a) +cn,where a >=1 and c>0 are constants.
6)Draw the recursion tree for t(n)=4T(n/2)+cn,where c is a constant,and provide a tight asymptotic bound on its solution.
7)Use a recursion tree to give an asymptotically tight solution to the recurrence T(n)=T(an)+T((1-a)n)+cn,where a is a constant in the range 0<>0 is also a constant.
8)Use master method to give tight asymptotic bounds for the following recurrences.
a.T(n)=4T(n/2)+n.
b.T(n)=4T(n/2)+n^3
9)The recurrence T(n)=7T(n/2)+n^2 describes the running time of an algorithm A.A completing algorithm A' has a running time of T'(n)=aT'(n/4)+n^2.What is the largest integer value for a such that A' is asymptotically faster than A?
10)Can the master method be applied to the recurrence T(n)=4T(n/2)+n^2(lg n)? Why or why not? Give an asymptotic upper bound for this recurrence.
11)Use the master method to show that the solution to the binary-search recurrence T(n)=T(n/2)+ Theta(1) is T(n)=Theta(lg n).
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The solutions link doesn't work do you think you can fix this? Thanks
ReplyDeletesorry,we also didn't observe this. give me 2 mins time to fix this.
ReplyDeletePlease find the updated link for solutions. we will put more solutions to this post asap.
ReplyDeleteplease answer all questions
ReplyDelete7)Use a recursion tree to give an asymptotically tight solution to the recurrence T(n)=T(an)+T((1-a)n)+cn,where a is a constant in the range 0<>0 is also a constant.
ReplyDeletesolution for que 5?
ReplyDeletewhat would be the solution to number 4?
ReplyDeleteT(n)=T(an)+T(1-n)a+cn
ReplyDeleteplese answer this recursion