2 solution) 9 9 56
3 solution) ans1: x*=y+1;
ans2:x*=++y,y--;
4 solution) emptystring or nthing
5 solution) First call can take an integer as input whether or not you put any spaces/newlines/white space characters before it.
But the second call expects at least one ' ' [ space ] character and then some/none white space characters and then an integer.
6 solution) 16
7 solution) 1111
8 solution) prints the numbers in 2 rows each containing 10 elements with in between spaces
9 solution) it won't because of overflow in the statement *a=*a+*b;
10 solution) 4 8
11 solution) 987641
12 solution) 2 1 2
13 solution) unsigned/**/int/**/p;
14 solution) 3 3 5 5
15 solution) output1:2 3
output2:2 4
16 solution) 111
17 solution) 82
18 solution) segmentation fault
19 solution) 15
20 solution) (nil)
21 solution) It prints the lower case letters present in the input
22 solution) 3 1
23 solution) 12
concatinate(1,2)
24 solution) *1 -> replacing '<' with '+' in the declaration of the loop #include
int main(){
int n = 42;
for(int i = 0; i + n; i-- )
printf("-");
return 0;
}
* 2 -> replacing n with i in the declaration of the loop
#include
int main(){
int n = 42;
for(int i = 0; i <> adding a '-' before i in the comparison in for loop
#include
int main(){
int n = 42;
for(int i = 0; -i < href="http://placementsindia.blogspot.com/2007/10/c-programming-questions.html"> click here for questions
thank you..
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