Basic C Questions to test ur expertise-3

What will be printed as the result
of the operation below:

int x;
int modifyvalue()

int changevalue(int x)

void main()
int x=10;
printf("First output:%d\n",x);

printf("Second output:%d\n",x);
printf("Third output:%d\n",x);


Answer: 12 , 13 , 13

What are the different storage classes in C?

C has three types of storage: automatic, static and allocated.

Variable having block scope and without static specifier have automatic storage duration.

Variables with block scope, and with static specifier have static scope. Global variables (i.e, file scope) with or without the the static specifier also have static scope.

Memory obtained from calls to malloc(), alloc() or realloc() belongs to allocated storage class.

What is the difference between strings and character arrays?

A major difference is: string will have static storage duration, whereas as a character array will not, unless it is explicity specified by using the static keyword.

Actually, a string is a character array with following properties:

* the multibyte character sequence, to which we generally call string, is used to initialize an array of static storage duration. The size of this array is just sufficient to contain these characters plus the terminating NUL character.

* it not specified what happens if this array, i.e., string, is modified.

* Two strings of same value[1] may share same memory area. For example, in the following declarations:

char *s1 = “Calvin and Hobbes”;
char *s2 = “Calvin and Hobbes”;

the strings pointed by s1 and s2 may reside in the same memory location. But, it is not true for the following:

char ca1[] = “Calvin and Hobbes”;
char ca2[] = “Calvin and Hobbes”;

[1] The value of a string is the sequence of the values of the contained characters, in order.

Write down the equivalent pointer expression for referring the same element a[i][j][k][l]?

a[i] == *(a+i)
a[i][j] == *(*(a+i)+j)
a[i][j][k] == *(*(*(a+i)+j)+k)
a[i][j][k][l] == *(*(*(*(a+i)+j)+k)+l)

Which bit wise operator is suitable for checking whether a particular bit is on or off?

The bitwise AND operator. Here is an example:

enum {
KBit0 = 1,


if ( some_int & KBit24 )
printf ( “Bit number 24 is ON\n” );
printf ( “Bit number 24 is OFF\n” );

Which bit wise operator is suitable for turning off a particular bit in a number?

The bitwise AND operator, again. In the following code snippet, the bit number 24 is reset to zero.
some_int = some_int & ~KBit24;

Which bit wise operator is suitable for putting on a particular bit in a number?

The bitwise OR operator. In the following code snippet, the bit number 24 is turned ON:
some_int = some_int | KBit24;

Does there exist any other function which can be used to convert an integer or a float to a string?

Some implementations provide a nonstandard function called itoa(), which converts an integer to string.


char *itoa(int value, char *string, int radix);

The itoa() function constructs a string representation of an integer.

Is the integer to be converted to string representation.

Points to the buffer that is to hold resulting string.
The resulting string may be as long as seventeen bytes.

Is the base of the number; must be in the range 2 - 36.

A portable solution exists. One can use sprintf():

char s[SOME_CONST];
int i = 10;
float f = 10.20;

sprintf ( s, “%d %f\n”, i, f );


  1. write a program that reads the multiplication table to numbers from 5 to 9

  2. I dont think ur enum is correct!!
    Is it not should be this way??
    KBit0 = 1,
    KBit1 = 2,
    KBit2 = 4,
    KBit3 = 8