tag:blogger.com,1999:blog-32064785.post1731991309438576097..comments2024-03-28T17:06:30.318+05:30Comments on Freshers Interviews: Solutions to Crazy Questions at Google Job Interviewchaitanyahttp://www.blogger.com/profile/05855949584266440305noreply@blogger.comBlogger13125tag:blogger.com,1999:blog-32064785.post-36438840611367086882012-01-30T15:57:43.907+05:302012-01-30T15:57:43.907+05:30Really awesome. I appreciate your work. Thank you....Really awesome. I appreciate your work. Thank you.<br /><br /><a href="http://www.campusrecruitments.com/Bank/bankupcomingexams.html" rel="nofollow">Upcoming Bank Exams</a>Educationhttps://www.blogger.com/profile/15632089902231469280noreply@blogger.comtag:blogger.com,1999:blog-32064785.post-43483828518033498942011-11-10T18:23:18.592+05:302011-11-10T18:23:18.592+05:30Great thoughts you got there, believe I may possib...Great thoughts you got there, believe I may possibly try just some of it throughout my daily life...<br /><br /><a href="http://jobinterviewtips.in/interview-question/" rel="nofollow">Job Interview Questions</a>Job Interview Questionshttps://www.blogger.com/profile/03444507713309741324noreply@blogger.comtag:blogger.com,1999:blog-32064785.post-65502328595358242242010-09-12T11:05:58.168+05:302010-09-12T11:05:58.168+05:30its too confusingits too confusingAnonymousnoreply@blogger.comtag:blogger.com,1999:blog-32064785.post-89138833092566453052010-03-07T19:06:01.540+05:302010-03-07T19:06:01.540+05:30Another Possible Solution to Problem 2.
A: Jump on...Another Possible Solution to Problem 2.<br />A: Jump onto a blade of the blender and hold the shaft of the blades tightly. Since you are now a part of the blade itself, they can't chop you.Siddhartha Maitrahttps://www.blogger.com/profile/03028582046434649664noreply@blogger.comtag:blogger.com,1999:blog-32064785.post-48993147217661505492010-02-16T02:54:46.022+05:302010-02-16T02:54:46.022+05:30a couple of these answers are wrong...a couple of these answers are wrong...Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-32064785.post-51820919120042096692010-02-08T05:57:53.727+05:302010-02-08T05:57:53.727+05:309 is not right too. you can find the solution on t...9 is not right too. you can find the solution on the net. all cheaters get killed at the end.Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-32064785.post-58669620045962260172009-11-19T02:31:58.347+05:302009-11-19T02:31:58.347+05:30"15. How many piano tuners are there in the e..."15. How many piano tuners are there in the entire world?<br /><br />Sum up all the numbers to get more or less accurate piano users count."<br /><br />Whoops, missed that one! Unless tuners == users, you've answered the wrong question.Unknownhttps://www.blogger.com/profile/18335773810277660859noreply@blogger.comtag:blogger.com,1999:blog-32064785.post-56217650686186928552009-11-05T22:07:50.049+05:302009-11-05T22:07:50.049+05:30Question 9 is wrong
If there are two cheated husba...Question 9 is wrong<br />If there are two cheated husbands, their wives won't kill them in the first day. On the next day they can figure out there are more than one cheated husbands and kill them.<br />If there are three cheated husbands, their wives won't kill them in the first and second day, so will kill in the third day. If all men are cheaters, all of them will be killed after 100 days.Morrisonnoreply@blogger.comtag:blogger.com,1999:blog-32064785.post-46041195063753244732009-07-18T00:21:26.772+05:302009-07-18T00:21:26.772+05:3010 isn't right. If you draw a branch diagram y...10 isn't right. If you draw a branch diagram you'll see the ratio is 1 to 1. One way to do it is make the simplifyign assumption that every 2 years a family will have a kid unless they have a boy and there are 16 families<br /><br />at year 0 <br />8 boys and <br />8 girls are born.<br /><br />at year 2<br />4 boys and<br />4 girls are born<br /><br />at year 4<br />2 boys and<br />2 girls are born<br /><br />etc<br /><br />the pirate problem is also technically right but the only way it works is if pirate 1 gives one coin to pirates 2 and 4. This is because of the heirarchy. You can solve with game theory if you assume that the highest rank pirate must divide the coins if the allocation was voted against and the previous top pirate was killed.Mikenoreply@blogger.comtag:blogger.com,1999:blog-32064785.post-70852760006799524762009-01-24T00:48:00.000+05:302009-01-24T00:48:00.000+05:30I disagree with your answer to 11.You wrongly assu...I disagree with your answer to 11.<BR/>You wrongly assume that any probability in any time period is dependant on any other time period that has passed or will pass. The question is not, for example "what is the likelyhood of seeing a car in a minute if you have not seen a car in the previous minute"<BR/>The traffic is a constant, independant of the observer - the cars will pass whether they are observed or not. <BR/>The traffic will not increase or decrease according to what has already passed, but the probability IS dependant on time.<BR/><BR/>a car passes on average every 30/0.95 = 31.57894737 minutes.<BR/>this will not increase just because you've already sat there watching nothing. If the probability of seeing a car in ANY 10 minute period during the day is 63% as you suggest, that would mean a car would pass on average every 10/0.6316 = 15.83 minutes which is not right.Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-32064785.post-30163093034121967992008-07-27T10:16:00.000+05:302008-07-27T10:16:00.000+05:30also check some good interview questions with answ...also check some good interview questions with answers at http://www.interviewduniya.comAnonymousnoreply@blogger.comtag:blogger.com,1999:blog-32064785.post-7297046339290752182008-07-20T12:47:00.000+05:302008-07-20T12:47:00.000+05:30about the overlaping hands...they didn't say they ...about the overlaping hands...they didn't say they overlap at the exact same point for an extended period of time, just overlap...it's impossible for them not to overlap less than 22 times a day, it's just that there's no point other than 12:00 where they overlap for a whole minute, but the split second where the minute hand passes over the hour hand counts, doesn't it?<BR/><BR/>my solution for number 8<BR/>get rid of some shirts, I don't need that many<BR/><BR/>and about #16<BR/>why not put 4 balls on each side of the balance, take two balls(one from each side), if the balance levels, then the one you took away from the heavier side is the heaviest, if not, repeat...i don't get why get so complicated as to put 6 balls first...cesårhttps://www.blogger.com/profile/15060267907896905474noreply@blogger.comtag:blogger.com,1999:blog-32064785.post-28605580047446909792008-07-11T09:11:00.000+05:302008-07-11T09:11:00.000+05:30Awsome Work man u r a geniousAwsome Work man u r a geniousAnonymousnoreply@blogger.com